Question

The horizontal distance between two trees of different height is 60m the angle of first tree when seen from top of second tree is 45 degre if height of second tree is 80m find height of first tree

Answer 1

Answer:

Step-by-step explanation:

Answer is of another question but you can change values according to this question and easily get the answer

Answer 2

Answer:

$\red { Height \: of \: the \: first \: tree }\green {=20\:m }$

Step-by-step explanation:

From the figure ;

Let the height of the first tree = AB = h m,

Height of the second tree = CE = 80 m

ED = CE - DE = (80 - h) m,

Distance between two trees = BC = AD = 60 m,

<DAE = 45°,

$In \: \triangle ADE ,\\</p><p>\angle DAE = 45\degree$

$tan \:45\degree = \frac{ED}{AD}$

$\implies 1 = \frac{ 80 - h }{60}$

$\implies 60 = 80 - h$

$\implies h = 80 - 60$

$\implies h = 20 \:m$

Therefore.,

$\red { Height \: of \: the \: first \: tree }\green {=20\:m }$

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