a rectangular hollow pipe is made of 1 cm thick iron sheet if the length of the pipe is 2 metre and the other outer dimensions of the pipe are 10 cm into 8 cm then find the weight of the pipe if 80cm cube of iron weighs 1 kg help fast
Answers
Answered by
1
In this type of question, we need to subtract external radius and internal radius to get the answer using the volume formula as the pipe is hollow. Oh! line become a bit complicated, sorry for that, lets solve it.
External radius = 5 cm
Internal radius = 3 cm [because thickness of pipe is 1 cm]
Volume of iron =πr2h
= 22/7∗[5^2−3^2]∗2m^3
= 22/7* [25 - 9 ] *2m^3
= 22/7* [16 ]* 2m^3
= 100 571.42 ^3
WEIGHT OF IRON - 100 571.42 * 10
HOPE YOU LIKED IT , PLEASE MARK ME AS BRAINLIEST
SO THAT I CAN HELP YOU AGAIN..... THANK YOU
External radius = 5 cm
Internal radius = 3 cm [because thickness of pipe is 1 cm]
Volume of iron =πr2h
= 22/7∗[5^2−3^2]∗2m^3
= 22/7* [25 - 9 ] *2m^3
= 22/7* [16 ]* 2m^3
= 100 571.42 ^3
WEIGHT OF IRON - 100 571.42 * 10
HOPE YOU LIKED IT , PLEASE MARK ME AS BRAINLIEST
SO THAT I CAN HELP YOU AGAIN..... THANK YOU
sarvagyaprasad:
Please mark me as brainliest... it took me a lots of time to answer your question
Similar questions
Business Studies,
7 months ago
Sociology,
7 months ago
Math,
1 year ago
Science,
1 year ago
Math,
1 year ago