Math, asked by sruthypotter3943, 1 year ago

A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is
A) rs.58
B) rs.158
C) rs.258
D) rs.358

Answers

Answered by PiyushSinghRajput1
9

Answer:   C) rs.258 

Explanation:

area of cross roads = (55 x 4) + (35 x 4)- (4 x 4) = 344sq m

cost of graveling = 344 x  (75/100) = Rs. 258

Answered by Anonymous
3
A rectangular lawn 55m by 35m has two roads each 4m wide running in the middle of it. One parallel to the length and the other parallel to breadth. The cost of graveling the roads at 75 paise per sq meter is
A) rs.58
B) rs.158
C) rs.258
D) rs.358

=> Option C

Description:

Crossed roads' area = (55 × 4) + (35 × 4) - (4 × 4) = 344 sq. m

Graveling's Cost = 344 × (74/ 100) = Rs. 258
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