Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
A) 30
B) 40
C) 50
D) 60
Answers
Answered by
2
Firstly we have to find the height so if base is 12cm and hypotenuse is 13cm and this is a right angled triangle
By Pythagoras theorem
13^2=12^2+height^2
Height^2=13^2-12^2
Height^2=169-144
Height^2=25
Height=√25
Height=5cm
Area of the triangle is
=1/2×base×height
=1/2×12×5
=30cm^2
Hope this helps
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Answered by
1
If you know Pythagoras triplet then
Base is 12 , hypotenuse is 13 so the opposite side is 5
By Pythagoras
(AC)=(AB)+(BC).
(13)=(AB)+(12). (Do square root of both numbers)
(AB)=169-144=25
AB=5
Area of right angle triangle
1/2xbxh
1/2x12x5.
30
Hope it will help you
Base is 12 , hypotenuse is 13 so the opposite side is 5
By Pythagoras
(AC)=(AB)+(BC).
(13)=(AB)+(12). (Do square root of both numbers)
(AB)=169-144=25
AB=5
Area of right angle triangle
1/2xbxh
1/2x12x5.
30
Hope it will help you
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