Math, asked by anuk9863, 1 year ago

Find the area of a right-angled triangle whose base is 12 cm and hypotenuse is 13cm.
A) 30
B) 40
C) 50
D) 60

Answers

Answered by Prajwalitapal044
2

Firstly we have to find the height so if base is 12cm and hypotenuse is 13cm and this is a right angled triangle

By Pythagoras theorem

13^2=12^2+height^2

Height^2=13^2-12^2

Height^2=169-144

Height^2=25

Height=√25

Height=5cm

Area of the triangle is

=1/2×base×height

=1/2×12×5

=30cm^2


Hope this helps

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Answered by anas2003
1
If you know Pythagoras triplet then
Base is 12 , hypotenuse is 13 so the opposite side is 5

By Pythagoras
(AC)=(AB)+(BC).
(13)=(AB)+(12). (Do square root of both numbers)

(AB)=169-144=25
AB=5

Area of right angle triangle
1/2xbxh
1/2x12x5.
30

Hope it will help you
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