Question

The difference between two parallel sides of a trapezium is 4 cm. perpendicular distance between them is 19 cm. If the area of the trapezium is 475 find the lengths of the parallel sides.
A) 27 and 23
B) 24 and 23
C) 25 and 23
D) 22 and 23

Answer 1

Answer:

A) 27 and 23

Step-by-step explanation:

Area of the trapezium = 475

Height = 19

Let the base be b1 and the parralel side to the base be b2.

As given, b1-b2=4 or b1=b2+4

Area of trapezium = 1/2*height (sum of parallel sides)

or 475 = 1/2*19*(b1+b2)

b1+b2 = 475*2/19

replacing b1 with b2+4 we get

b2+4+b2 = 50

2*b2 = 46

b2 = 23

hence b1 = 23+4 = 27

Hence the lengths of non-parallel sides are 27 & 23.