a rectangular lawn measuring 50 m by 36 m is surrounded externally by path which is 2m wide .Find the area of path.
Answers
Answered by
43
Dimensions of inner rectangle is : L = 50 and B= 36
So,
Area of inner rectangle = lb
=50×36
=1800m²
Dimensions of outer rectangle : L=50+4 =54 and B = 36+4 =40
So,
Area of outer rectangle = 54×40
=2160m²
Now,
Area of path = Area of outer rect. - area of inner rect.
=360m² Ans.
So,
Area of inner rectangle = lb
=50×36
=1800m²
Dimensions of outer rectangle : L=50+4 =54 and B = 36+4 =40
So,
Area of outer rectangle = 54×40
=2160m²
Now,
Area of path = Area of outer rect. - area of inner rect.
=360m² Ans.
Deveshmeena:
hay
Answered by
24
Question:-
a rectangular lawn measuring 50 m by 36 m is surrounded externally by a path which is 2 m wide . find the area of the path .
solution:-
Let, L be the length of rectangle and B be the breadth rectangle.
By Question:-
We know formula of
=> Area of rectangle = L × B
=> Area of rectangle = 50 × 36
=> Area of rectangle = 1800 m²
=> X = 1800 m²
we know that length and breadth increase by 2 m from their both ends.
so,
=> L = 50 + 2 + 2 = 54 m.
=> B = 36 + 2 + 2 = 40 m.
We know formula of
=> Area of rectangle + path = L × B
=> Area of rectangle + path
= 54 × 40
=> Area of rectangle + path
= 2160 m²
=> Z = 2160 m²
=> Area of path =( Z ) - ( X )
=> Area of path = 2160 - 1800
=> Area of path = 360 m²
Area of path 360 m².
i hope it helps you.
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