Math, asked by Deveshmeena, 1 year ago

a rectangular lawn measuring 50 m by 36 m is surrounded externally by path which is 2m wide .Find the area of path.

Answers

Answered by SanjeevV
43
Dimensions of inner rectangle is : L = 50 and B= 36
So,
Area of inner rectangle = lb
=50×36
=1800m²
Dimensions of outer rectangle : L=50+4 =54 and B = 36+4 =40
So,
Area of outer rectangle = 54×40
=2160m²
Now,
Area of path = Area of outer rect. - area of inner rect.
=360m² Ans.

Deveshmeena: hay
Answered by nilesh102
24

Question:-

a rectangular lawn measuring 50 m by 36 m is surrounded externally by a path which is 2 m wide . find the area of the path .

solution:-

Let, L be the length of rectangle and B be the breadth rectangle.

By Question:-

We know formula of

=> Area of rectangle = L × B

=> Area of rectangle = 50 × 36

=> Area of rectangle = 1800 m²

=> X = 1800

we know that length and breadth increase by 2 m from their both ends.

so,

=> L = 50 + 2 + 2 = 54 m.

=> B = 36 + 2 + 2 = 40 m.

We know formula of

=> Area of rectangle + path = L × B

=> Area of rectangle + path

= 54 × 40

=> Area of rectangle + path

= 2160 m²

=> Z = 2160

=> Area of path =( Z ) - ( X )

=> Area of path = 2160 - 1800

=> Area of path = 360 m²

Area of path 360 m².

i hope it helps you.

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