Math, asked by veenapanising, 1 year ago

in a examination, there were 320 boys and 180 girls. 60% of boys and 80% of girls passed. find the percentage of failure students

Answers

Answered by Golda
8
Solution :-

Total number of boys + girls appeared in the examination = 320 + 180 = 500 students

Total number of boys = 320

Boys passed = 60 % 

Boys failed = 100 - 60 = 40 % 

Total number of boys failed = (40*320)/100

= 128 Boys failed out of 320 boys.

Total number of girls = 180

Girls passed = 80 %

Girls failed = 100 - 80 = 20 %

Total number of girls failed = (20*180)/100

= 36 girls failed

Total number of boys + girls failed = 128 + 36 = 164 Students

Percentage of failed students = (164*100)/500

= 32.8 %

Answer.
Answered by nikitasingh79
4
Given: 

No. of boys= 320
No. of girls= 180

Total no. of students = 180+320=500

No. of boys passed= 60% of 320= (60/100) ×320 = 192

No. of boys failed = 320- 192= 128

No. of girls passed = 80% of 180 = (80/100) ×180= 144

No. of girls failed = 180-144= 36

Total students failed = 128=36= 164

% of students failed = (No. of failed students/ total students) ×100

% of students failed = (164 /500) ×100= 164/5 =32.8% 
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The percentage of failure students= 32.8 %
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Hope this will help you......
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