Math, asked by satish6633, 11 months ago

A rectangular loop of sides 10cm and 5cm carrying a current

Answers

Answered by alokclans123

0

Answer:

Then ,

Area of loop = l × b

= 10 × 5 = 50 cm^2

Answered by ANGEL123401

2

Answer:

Area of loop = l×b

given l=10 cm

b=5cm

hence,l×b=(10cm×50cm)

=50cm^2

Hope it helps you ❣️☑️☑️

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