Question

A rectangular paper, when folded into two congruent parts had a perimeter of 34 cm foer each part folded along one set of sides and the same is 38cm. When folded along the other set of sides. What is the area of the paper?​

Answer 1

Answer:

When folded along the breadth, we have

2(l/2 + b) = 34

=> l + 2b = 34 ... ( i )

When folded along the length, we have

2(l+b/2) = 38

=> 2l + b = 38 ...( ii )

From ( i ) we have,

l = 34 – 2b

Putting in ( ii ),

2(34 – 2b) + b = 38

=> 68 – 3b = 38

=> 3b = 30

=> b = 10

From ( i ), l + 20 = 34 => l = 14

Therefore area of paper = l × b

$(14 \times 10)m {}^{2}$

= $140m {}^{2}$