Math, asked by jitu4017, 1 year ago

a rectangular Park 45 m by 20 m is to be surrounded by a path 3 M wide find the area of the calculated the cost of levelling the path at rate of rupees 2.50 per square metre

Answers

Answered by Anonymous
36
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 \implies{ \tiny{ \mathsf{Length \: AB = 40 m \: \: and \: \: breadth \: \: BC = \: 20 m}}} \\ \\ \\ \implies{ \tiny{ \mathsf{Area \: \: of \: lawn \: ABCD \: = 45 \: m \times 20 \: m \: = \: 900m}}} \\ \\ \\ \implies{ \tiny{ \mathsf{Length \: \: PQ \: = \: (45+ 3+ 3 ) \: m = \: 51 m}}} \\ \\ \\ \implies{ \tiny{ \mathsf{Breadth \: QR \: = \: ( 20+ 3 + 3 ) m \: = 26 m}}} \\ \\ \implies{ \tiny{ \mathsf{Area \: \: of \: PQRS \: = \: 51 m \times 26 m \: = 1326 m}}} \\ \\ \\ \\ \implies{ \tiny{ \mathsf{Now, \: \: Area \: of \: the \: path = \: Area \: of \: PQRS \: - Area \: of \: the \: lawn \: ABCD}}} \\ \\ \\ \implies{ \tiny{ \mathsf{1326 - 900 = 426}}} \\ \\ \\ \implies{ \tiny{ \mathsf{Rate \: of \: \: leveling \: the \: path = \: Rs. 2.50 \: per \: \: {m}^{2}}}} \\ \\ \\ \\ \implies{ \tiny{ \mathsf{Cost \: of \: leveling \: the \: path = Rs. \: \: 2.50 \times 426= 1065}}}

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