A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and the rest of the park has been used as a lawn. What is the width of the road if the area of the lawn is 2109 m2?
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Answer:
length = 6om
breadth=40m
area of the park=6ox 40=2400m2
area of the lawn=2109m2
area of the cross roads=24oo-2109
=291m2
The width of the road be x m
(6o-x) x+(4o-x) x=291
6ox-x2+4ox-x2=29 I
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