Question

A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

Answer 1

Solution:-

Area of the park = (60 x 40) m^2 = 2400 m^2.

Area of the lawn = 2109 m^2

=> Area of the crossroads = (2400 - 2109) m^2 = 291 m^2.

Now, let the width of the road be x metres.

Then,
60x + 40x - x^2 = 291

=> x^2 - 100x + 291 = 0

=> (x - 97)(x - 3) = 0

=> x = 3 m