The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:
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Let original L= x m and original b = y metres.
Original area = xy
Increased length =120/100 x
Increased breadth = 120/100 y
New area = 120/100x × 120/100 y=36/25 x y m²
The differ b/w original a and new a. = 36/25 xy - xy =11/25 xy
Increase % =11/25 xy /xy ×100
= 44%
hope this will help u...plz react thanks
Original area = xy
Increased length =120/100 x
Increased breadth = 120/100 y
New area = 120/100x × 120/100 y=36/25 x y m²
The differ b/w original a and new a. = 36/25 xy - xy =11/25 xy
Increase % =11/25 xy /xy ×100
= 44%
hope this will help u...plz react thanks
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