A rectangular park 60 m long and 40 m wide has two concrete crossroads
running in the middle of the park and rest of the park has been used as a lawn. If the
area of the lawn is 2109 sq.m, then what is the width of the road?
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Answered by
3
Area of the park = (60 x 40) m2 = 2400 m2. Area of the lawn = 2109 m2. Area of the crossroads = (2400 - 2109) m2 = 291 m
Answered by
2
Answer:
3
Step-by-step explanation:
Area of the park = (60 x 40) = 2400m²
Area of the lawn = 2109m²
Area of the crossroads = (2400 - 2109) = 291m²
Let the width of the road be x metres. Then,
60x+40x−X2=291
x²−100x+291=0
(x - 97)(x - 3) = 0
x = 3.
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