A rectangular park 70m*30m has two roads, which are 5m wide,one parallel to its and the other to its breadth.how much will it cost to gravel the roads as rs 4 per sq m?
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Answered by
3
lxb-(l-5)x(b-5) = 2100-1625=475 sq m
cost of gravel = 475x4=1900
cost of gravel = 475x4=1900
rajii:
pls give me clear explanation..
We know that area of rectangle is = lxb
but here we have two roads which are crossing each other at a point
k thank u ...
means 1 is parallel to length and other to breadth,
So we will minus the Roads area with lenght and breadth
==> L= L-5 and B =B-5
So then we will minus the new area from where we have subtracted the road parts from the older one.
So we will minus the Roads area with lenght and breadth
==> L= L-5 and B =B-5
So then we will minus the new area from where we have subtracted the road parts from the older one.
= lxb-(l-5)x(B-5)
= 70x30-65x25
2100-1625=475
Road area= 475
Total cost =475x4 1900Rs
= 70x30-65x25
2100-1625=475
Road area= 475
Total cost =475x4 1900Rs
Answered by
0
area o f park=70*30
area of roads=total area-area of park
75*35-70*30
2625-2100
525
cost of gravel = 525*4
2100
area of roads=total area-area of park
75*35-70*30
2625-2100
525
cost of gravel = 525*4
2100
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