Question

A rectangular park is 25m long and 10m wide. If a 3m wide path is constructed just outside the periphery of the park. Find the area of the path.


Any one explain it

Answer 1

Answer:

246 m²

Step-by-step explanation:

Given, Length = 25 m.

Given, Breadth = 10 m.

Area of garden = 25 * 10

                         = 250 m²

Given that a 3m wide path is constructed just outside the park.

New length = 25 + 2 * 3

                   = 31 m.

New Breadth = 10 + 2 * 3

                      = 16 m.

So, Area of rectangular park with path = 31 * 16 = 496 m²

∴ Area of the path = Area of rectangular park with path - without path.

                              = 496 - 250

                              = 246 m²

Therefore, Area of the path = 246 m²

Hope it helps!

Answer 2

SOLUTION :

The length of rectangular park = 25 m      (given)

The breadth of rectangular park = 10 m      (given)

Let

The rectangular park be ABCD

AB = DC (each 25 m)

AD = BC (each 10 m)

Area of the rectangular park = lb unit sq.

[ In which l is the length and b is the breadth of the rectangular park ]

So,

Area of the rectangular park = 25 × 10 = 250 m sq.

According to the question,

3 m wide park is constructed just outside the periphery of the park

To be found :-

Area of the path

Here

A new rectangle has been formed PQRS

So,

Each side increased by 3 m

AB = DC (each 25 m)

AD = BC (each 10 m)

PQ = SR (each = 25+3+3 = 31 m)  lengths

PS = QR (each = 10+3+3 =16 m)  breadths

Now,

Area of the new rectangle = lb unit sq.

[ In which l is the length and b is the breadth of the rectangular park ]

So,

Area of the rectangle PQRS = 31 × 16 = 496 m sq.

Area of the path = Area of PQRS - Area of ABCD

Area of the path = 496 m sq. - 250 m sq.

Area of the path = 246 m sq.

Hence

Area of the park is 246 m sq.