A rectangular peace of a paper of dimension 30 cm ,14cm is rolled to form a hollow circular cylinder , then find the curved surface area of the cylinder
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Answer:
The curved surface area of the cylinder is 520cm²
Step-by-step explanation:
Given that,
- A rectangular piece of paper of dimension 30cm × 14cm is rolled and formed a hollow cylinder.
Here, The rectangular piece of paper is rolled to hollow cylinder. we need to find the curved surface area of the cylinder.
So, After rolling into hollow cylinder.
The dimension of the cylinder will be :
→ Circumstance (2πr) = 30cm.
→ Height (h) = 14cm.
→ C. S. A. (Curved surface area) of a cylinder is given by : 2πrh
We have,
- → 2πr (circumstance) = 30cm.
- → h (height) = 14cm.
From the given given dimension :
→ C. S. A. of the cylinder :
→ (30 • 14)cm²
→ 520cm²
∴ The curved surface area of the cylinder is 520cm² ✔
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