Question

A rectangular piece of ground is 45 metre long and 30 m wide it has two roads each one wide running midway within it, parallel to length and one parallel to breadth. Find the area of the rules also calculate the area of the remaining ground.
Please answer it​

Answer 1

BRO I DON'T KNOW THIS ANSWER SORRY!!!

Answer 2

Answer :

• Area of the remaining roads is 1276m²

Given :

• Length is 45m
• breadth is 30m

To find :

• Area of the remaining ground

Solution :

Given ,

• length is 45m
• breadth is 30m

• Area of rectangular piece of ground = length × breadth

● 45 × 30

● 1350m²

Area of rectangular piece of ground is 1350m²

Now ,

According To Question, it has two roads each one wide running midway within it, parallel to length and one parallel to breadth then ,

• Length of 1st parallel road to the length is 45m
• breadth of 1st road parallel to the length is 1m

● Area of 1st road = 45 × 1

● = 45 m²

Area of 1st road is 45m²

• Length of 2nd parallel road to the breadth is 30m
• Breadth of 2nd parallel road to the breadth is 1m

● Area of 2nd road = 30 × 1

● 30m²

Area of 2nd road is 30m²

• Area of common part of two roads = 1 × 1 = 1m²

Now we have to find the total areas of two road :

• total areas of two roads = Area of 1st road + area of 2nd road - area of common part

● (45 + 30) - 1

● 75 - 1

● 74 m²

Area of two roads is 74m²

Now we have to find the area of the remaining roads:

• Area of remaining roads = area of the rectangular piece of ground - area of two roads

● 1350 - 74

● 1276 m²

Hence , Area of the remaining roads is 1276m²