a rectangular piece of ground is 45 metre long and 30 metre wide it has two roads each 1 metre wide running Midway within it on parallel to the length and the other parallel to the breadth find the area of rod also calculate the area of the remaining round
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Area of 1st Road = 45 m × 1m =
45 m²
Area of 2nd Road = 30 m × 1 m =
30 m²
Area of common part = 1 m × 1 m =
1 m²
Area of road = 45 m² + 30 m ² - 1 m² =
74 m²
Area of total ground = 45 m × 30 m =
1350 m².
HENCE the area of remaining ground =
1350 m² - 74 m² = 1, 276 m².
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