A rectangular piece of paper 11 cm × 14 cm is folded without overlapping to make a cylinder of height 14 cm. Find the volume of the cylinder.
Answers
Answer:
Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm
The length of the paper becomes the circumference of the base of the cylinder and width becomes height.
Let radius of the cylinder=r and height=h
Circumference of the base of cylinder =2πr=11cm
⇒2×
7
22
×r=11
∴r=
4
7
cm
Now h=4cm
Volume of the cylinder (V)=πr
2
h
=
7
22
×
4
7
×
4
7
×4cm
3
=38.5cm
3
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Answer:
38.5 cm³
Step-by-step explanation:
Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm
The length of the paper becomes the circumference of the base of the cylinder and width becomes height.
Let radius of the cylinder=r and height=h
Circumference of the base of cylinder =2πr=11cm
= 2 × 22/7 × r = 11
Therefore, r = 7/4 cm
Now h=4cm
Volume of the cylinder (V)=πr²h
= 22/7 × 7/4 × 7/4 = 4 cm³
= 38.5 cm³
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