Question

A rectangular piece of paper 11 cm × 4 cm is folded without overlapping to make a cylinder of height 4 cm. Find the volume of the cylinder ​

Answer 1

Step-by-step explanation:

Answer

Given a Rectangular piece of paper 11cm×4cm is folded without overlapping to make a cylinder of height 4 cm

The length of the paper becomes the circumference of the base of the cylinder and width becomes height.

Let radius of the cylinder=r and height=h

Circumference of the base of cylinder =2πr=11cm

⇒2× 22/7 ×r=11

∴r= 47cm

Now h=4cm

Volume of the cylinder (V)=πr^2

= 22/7× 4/7 × 4/7×4cm

=38.5cm

Answer 2

Answer:

38.5cm³ is the answer.

Let radius of the cylinder=r and height=h

Circumference of the base of cylinder =2πr=11cm

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11∴r=47cm

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11∴r=47cm

Now h=4cm

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11∴r=47cm 

Now h=4cmVolume of the cylinder (V)=πr2h

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11∴r=47cm 

Now h=4cmVolume of the cylinder (V)=πr2h=722×47×47×4cm3

Circumference of the base of cylinder =2πr=11cm⇒2×722×r=11∴r=47cm

 Now h=4cmVolume of the cylinder (V)=πr2h=722×47×47×4cm3

=38.5cm3