Question

a rectangular piece of paper 11 cm× 4cm is folded without overlapping to make a cylinder of height 4cm. find the volume of the cylinder
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Answer 1

Answer:

38.5cm3

Step-by-step explanation:

at first the length of the rectangle is 11cm

so if we change it into a cylinder then the circumference of its base will be 11cm

so r= 7/4cm

h of the cylinder is 4cm

so v of the cylinder is pier2h

22/7×7/4×7/4×4=77/2=38.5cm3.

Answer 2

Answer:

$\small{\boxed{\bold {The\:volume\:of \:cylinder\:is\:38.5cm^3}}}$

$\tt{Given}\begin{cases}\tt{11cm} \\ \tt{4cm} \\\tt{4cm}\end{cases}$

$\large\underline\textsf{To find }$

$\small\textsf{the volume of the cylinder }$

$\large\underline\textsf{Suppose:- }$

$\large\bf{ Radius \:of \:cylinder =\red R}$

$\large\bf{And \:Hieght =\red H}$

$\huge\underline\textsf{Explantion:- }$

$\implies\sf perimeter \: of \: the \: base \: of \: the \: cylinder = 2\pi \: r = 11$

$\implies\sf2 \times \frac{22}{7} \times r = 11$

$\implies\sf r = \frac{7}{4} cm$

$\implies\sf volume \: of \: cylinder = v = \pi \: r {}^{2} h$

$\implies\sf \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4cm {}^{3}$

$\leadsto\bf38.5cm {}^{3}$