a rectangular piece of paper 11cm*4cm is folded without overlapping to make a cylinder of height 4cm . find the surface area of the closed cylinder.
Class 10 please help fast we ith correct answer
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Answer:
Circumference of base of cylinder = 11cm
2*pi*r = 11
So r = 11/(2*pi). → retain as such for easy calculation
Volume of cylinder = pi*(r^2)*h
Substituting for r,
pi*((11/(2*pi))^2)*4
= 11*11*4/(4*pi)
= 11*11*7/22 (using pi=22/7)
= 77/2
= 38.5 cu cm
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Answer:
the correct answer is 38.5 cu cm
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I hope it helps
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