a rectangular piece of paper 33cm×20 cm is folded to make a cylinder of height 20cm. find volume of the cylinder assuming there is no overlapping of paper
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In this question , Height of the cylinder = 6 cm.
And , Circumference of the base = 22 cm
So, 2*22/7*r = 22.
i.e. r = 7/2 cm.
Apply the formula of volume of cylinder = 22/7*r^2*h
i.e. 22/7 * 7/2 * 7/2* 6 cubic cm = 231 cubic cm.
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And , Circumference of the base = 22 cm
So, 2*22/7*r = 22.
i.e. r = 7/2 cm.
Apply the formula of volume of cylinder = 22/7*r^2*h
i.e. 22/7 * 7/2 * 7/2* 6 cubic cm = 231 cubic cm.
Hope this helps u
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Step-by-step explanation:
Radius = ?
Height = 20 cm
Length = 33 cm
Breadth = 20 cm
base of cylinder = 2pie r
33 = 2X22/7X r
33= 44/7 r
r= 33X7/44 = 21/4cm
vol. of cylinder = pie r^h
= 22/7X 21/7X21/7X20
= 22X3/1X3/7X20
= 22X9X20/7
= 22X180/7
= 3960/7
= 565.71 cm( cube)
HOPE IT IS HELPFUL ...........
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