a rectangular piece of paper is 22 CM in length and 10 cm in width it is rolled into a cylinder along its length find the surface area of the cylinder
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this the surface area
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First of a length is made to be circumference of the cylinder. Width is the height.
2πr = 22
πr = 11
r = 11*7/22 = 3.5 cm.
Height h = 10 cm.
TSA of cylinder = 2 πr(h + r) = 2(22/7(3.5)(13.5) )
= 22* 13.5
= 297 cm² .
2πr = 22
πr = 11
r = 11*7/22 = 3.5 cm.
Height h = 10 cm.
TSA of cylinder = 2 πr(h + r) = 2(22/7(3.5)(13.5) )
= 22* 13.5
= 297 cm² .
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