Question

a rectangular piece of paper is 22 CM in length and 10 cm in width it is rolled into a cylinder along its length find the surface area of the cylinder

Answer 1

this the surface area

Answer 2

First of a length is made to be circumference of the cylinder. Width is the height.

2πr = 22

πr = 11

r = 11*7/22 = 3.5 cm.

Height h = 10 cm.

TSA of cylinder = 2 πr(h + r) = 2(22/7(3.5)(13.5) )

= 22* 13.5

= 297 cm² .