A rectangular piece of paper is 22 cm in length and 10 cm in width . it is rolled into a cylinder along its length . find the surface area of this cylinder
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☆Hello friend☆
22 cm will become circumference, and 10 cm height.
22cm=2×22/7 × r
22cm=44r/7
22×7/44=r
3.5 cm=radius
SA= 2 ×22/7 ×3.5(10+3.5)
SA= 44×0.5×13.5
Surface area =297 cm^2
Hope it helps
☺☺☺
22 cm will become circumference, and 10 cm height.
22cm=2×22/7 × r
22cm=44r/7
22×7/44=r
3.5 cm=radius
SA= 2 ×22/7 ×3.5(10+3.5)
SA= 44×0.5×13.5
Surface area =297 cm^2
Hope it helps
☺☺☺
ayush649:
22×10=surface area of cylinder
220 =surface area of cylinder
okk, this question in new to mee
I have done many like this but never used this concept
is question mea total surface are nhi pucha hai
okkk
but its too small
are nhi area
and u know how to do it
my father helped me
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Solutions
length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Total surface area = 220 +2 x (22/7)x 3.5²
= 220 + 77
= 297 cm²
Thanks
length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Total surface area = 220 +2 x (22/7)x 3.5²
= 220 + 77
= 297 cm²
Thanks
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