a rectangular piece of paper is 22 CM in length and 10 cm in width. It is rolled into a cylinder along its length. Find the surface area of this cylinder.
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thanks for answer but question ask the area of cylinder not area of rectangle
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length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Thanks
length of paper = Circumference = 22 cm
Width of paper = height of cylinder = 10 cm
Then,
Circumference of circle = 22 cm
=> 2πr = 22
=> 2x(22/7) x r = 22
=> r = 7/2 = 3.5 cm
Now,
Curved Surface Area of cylinder = 2πrh
= 2 x (22/7) x 3.5 x 10
= 220 cm²
Thanks
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