Question

A rectangular piece of paper is having measures 11cm * 4cm. It is folded without overlapping to make a cylinder of height 4cm. Find the volume of the cylinder

Answer 1

Length of recatngular piece=11cm
breadth of rectangular piece =4cm

Area of
rectangular piece =Curved surface of cylinder
11×4=2pie r h
44=2 ×22/7 ×r×4 (since hieght=4cm)

44×7/2×22×4=r


r=1.75cm

volume of cylinder=1/3×pie ×r^2×h
=1/3×22/7 ×1.75×1.75×4

=22/21 ×12.25
=12.833cm^3

Answer 2

Answer:

$\small{\boxed{\bf {The\:volume\:of \:cylinder\:is\:38.5cm^3}}}$

$\tt{Given}\begin{cases}\tt{11cm} \\ \tt{4cm} \\\tt{4cm}\end{cases}$

$\large\underline\textsf{To find }$

$\small\textsf{the volume of the cylinder }$

$\large\underline\textsf{Suppose:- }$

$\large\bf{ Radius \:of \:cylinder =\red R}$

$\large\bf{And \:Hieght =\red H}$

$\huge\underline\textsf{Explantion:- }$

$\implies\sf perimeter \: of \: the \: base \: of \: the \: cylinder = 2\pi \: r = 11$

$\implies\sf2 \times \frac{22}{7} \times r = 11$

$\implies\sf r = \frac{7}{4} cm$

$\implies\sf volume \: of \: cylinder = v = \pi \: r {}^{2} h$

$\implies\sf \frac{22}{7} \times \frac{7}{4} \times \frac{7}{4} \times 4cm {}^{3}$

$\leadsto\bf38.5cm {}^{3}$