Question

A rectangular playground is 65 my long and 30 my wide. a pathway of 1.5m width goes all around the ground , outside it. fid the area of the pathway

Answer 1

area of path is (2L+x)(2B+x)-L*B
x=1.5m width of path
according to question,
= (2*65+1.5)(2*30+1.5)-65*30
= (130+1.5)(60+1.5)-1,950
= 131.5*61.5-1950
= 8,087.25-1950
= 6,137.25
Answer= Area of path is 6,137.25square metre

Answer 2

Hello..
Answer..

$given \: that \: \\ a \: recangularplay \: ground \: \\ length = 65m \\ breadth = 30m \\ area = lengh \times breadth \\ = 65 \times 30 = 1950m \\ \\ a \: pathway \: of \: 1.5m \: width \: goes \: all \: around \: the \: ground \: out \:side \: it. \\ so \:. \\ new \: length + 1.5 + 1.5 \\ = 65 + 1.5 + 1.5 = 68 \\ \\ new \: breadth + 1.5 + 1.5 \\ = 30 + 1.5 + 1.5 = 33 \\ \\ new \: area = 68 \times 33 = 2244m \\ \\ so \: the \: area \: of \: the \: pathway \: will \: be \: \\ 2244 - 1950 = 294m$
It may be wrong, I'm not sure about the answer.

If it's wrong, please report it..

☺ ☺ ☺