Math, asked by AniruddhPratapSingh, 1 day ago

A rectangular plot is fenced with 150 m long wire. Find the dimensions of the plot if its length is twice its breadth.​

Answers

Answered by luxmansilori
3

Fence= perimeter of field=150

let breadth be x

length=2x

2(2x+x)=150

3x=75

x=25

l=50m

b=25 m

Answered by kumudinisingh2018
0

Answer:

Length = 50 meters

Breadth = 25 meters

Step-by-step explanation:

Let's denote the breadth of the rectangular plot as "b" meters. According to the given information, the length of the rectangular plot is twice its breadth, so the length would be "2b" meters.

The perimeter of a rectangle is given by the formula: Perimeter = 2 × (Length + Breadth).

Given that the total length of the wire used to fence the rectangular plot is 150 meters, we can set up the following equation:

2 × (2b + b) = 150

Simplifying the equation, we get:

2 × 3b = 150

6b = 150

Dividing both sides by 6, we get:

b = 150 / 6

b = 25

So, the breadth of the rectangular plot is 25 meters.

Since the length is twice the breadth, the length would be:

2b = 2 × 25 = 50

So, the length of the rectangular plot is 50 meters.

Therefore, the dimensions of the rectangular plot are:

Length = 50 meters

Breadth = 25 meters

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