A rectangular plot of field measures 12 m by 15 m a pit 8 m by 6 m by 50 M is dug in the field and soil remove it is spread evenly over the remaining portion of the field find the increase in the level of the remaining portion of the field.
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Answer:
Area of field = 12×15 m²
= 180 m²
volume of pit = 8m × 6m × 0.50m
= 24m³
Area of pit = 8m × 6m
=48m²
Area of remaining portion =
180m² — 48m²
132m²
Height raised = 24m³÷132m²
= 0.1818 m
= 18.18 cm. Answer.
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