a rectangular plot of grass, which is 22.5 m long and 24.4 m broad , has a 1.5 m wide road outside it. Find the area of the road.--------answer158.70m²
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15
See the attached figure;
Area of road = Area of shaded part
Area of shaded part = Area of rectangle PQRS - Area of rectangle ABCD
For rectangle ABCD,
Length = 22.5 m
Breadth = 24.4 m
So Area = Length × Breadth
Area of rec. ABCD = 22.5m × 24.4m = 549 m
Now For rectangle PQRS,
Length = Length AB + 1.5 +1.5
Length = 22.5 +1.5+1.5
Length = 25.5 m
Breadth = Breadth AD + 1.5+1.5
Breadth = 24.4 + 1.5+1.5
Breadth = 27.4 m
Area = 25.5 × 27.4 = 698.7m^2
Now Area of road = 698.7-549
Area of road = 149.7
Area of road = Area of shaded part
Area of shaded part = Area of rectangle PQRS - Area of rectangle ABCD
For rectangle ABCD,
Length = 22.5 m
Breadth = 24.4 m
So Area = Length × Breadth
Area of rec. ABCD = 22.5m × 24.4m = 549 m
Now For rectangle PQRS,
Length = Length AB + 1.5 +1.5
Length = 22.5 +1.5+1.5
Length = 25.5 m
Breadth = Breadth AD + 1.5+1.5
Breadth = 24.4 + 1.5+1.5
Breadth = 27.4 m
Area = 25.5 × 27.4 = 698.7m^2
Now Area of road = 698.7-549
Area of road = 149.7
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Answer:
Let ABCD be the plot of grass and PQRS is the road
Now,
AB = 25.5 m and BC = 24.4 m
Then ,
PQ = (25.5+ 1.5+ 1.5) m = 28.5 m
QR = (24.4 + 1.5 + 1.5) m= 27.4m
Therefore sign will be required Area of PQRS = 28.5 × 27.4 = 780.90m
Therefore Sign will be required, Area of ABCD = 25.5 ×24.4 = 622.20 m
Therefore sign will be required, Area of the road = ( 780.90 -- 622.20 ) subtract
158.70 m square .
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