Question

Find the quadratic polynomial as sum and product of zeros are -1/4 and 1/4 respectively.
Plz give me answer fastly

Answer 1

Quadratic Equation is given by :-

$\bold {k(x^2-(sum of zeroes)x+(product of zeroes)}$

So

Sum of zeroes = -1/4
Product of zeroes = 1/4

Put in formula ;

$\bold {k(x^2-(sum of zeroes)x+(product of zeroes)}$

$\bold {k(x^2-(-1/4)x+(1/4)}$

$\bold {k(x^2+1/4 x + 1/4}$

Multiply equation by 4

$\bold {k(4x^2+x+1)}$

Here k = 1

Answer 2

Answer:

$4x^{2} +x+1$

Step-by-step explanation:

let as assume the zeros be a and b.

a+b= -1/4

ab = 1/4

Quadratic polynomials

$x^{2} -(a+b)x+ab\\x^{2} +1/4x+1/4\\4x^{2} +x+1$