Question

A rectangular plot of land is 103/4m long and 47/3m wide. find the perimeter and area of the plot​

Answer 1

$2(l + b) \\ 2( \frac{103}{4} + \frac{47}{3} ) \\ 2( \frac{309 + 188}{12} ) \\ 2( \frac{497}{12} ) \\ 2 \times \frac{497}{12} (now \: we \: will \: cut \: 12 \: by \: 2) \\ \frac{497}{6} \\ 82.83 \: answer$

Answer 2

Question :

A rectangular plot of land is 103/4 m long and 47/3 m wide. Find the perimeter and area of the plot.

Solution :

$\underline{\bold{Given:}}$

• $Length \: of \: the \: rectangular \:plot = \frac{103}{4} \: m$
• $Breadth \: of \: the \: rectangular \: plot = \frac{47}{3} \: m$

$\underline{\bold{To\:Find:}}$

• Perimeter of the plot.
• Area of the plot.

$\fbox{\pink{Perimeter=2 (length +breadth)}}$

$\implies Perimeter=2 (length +breadth) \\ \implies Perimeter=2 ( \frac{103}{4} \: m + \frac{47}{3} \: m) \\ \implies Perimeter=2 (\frac{309 +188 }{12} \: m) \\ \implies Perimeter=2 \times \frac{497}{12} \: m \\ \implies Perimeter = \frac{497}{6} \: m \\ \implies Perimeter = 82 \frac{5}{6} \: m$

$\boxed{\green{\therefore{Perimeter\:of\:the\:plot=82 \frac{5}{6} \: m}}}$

$\rule{193}{1}$

$\boxed{\blue{Area=length\times breadth}}$

$\implies Area=length \times breadth \\ \implies Area= \frac{103}{4} \: m \times \frac{47}{3} \: m \\ \implies Area= \frac{4841}{12} \: m^2 \\ \implies Area=403 \frac{5}{12} \: m^2$

$\boxed{\green{\therefore{Area\:of\:the\:plot=403\frac{5}{12} \: m^2}}}$

$\rule{193}{2}$

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