Question

a rectangular plot of land measures 41m in length and 22.5 in width. a boundary wall 2m high is built all around the plot at a distance of 1.5m from plot l. find the inner surface area of boundary wall

Answer 1

Height of wall=2m

Now,if the wall is 1.5m from the plot then length =41+3=44m

And,breadth =22.5 + 3 =25.5m

Surface area of wall =2(25.5×2)+2(44×2)

i.e,2(51+88)

Therefore, surface area of wall is 278m square