A rectangular pool 20 meters wide and 60 meters long is surrounded by a walkway of uniform width. of the total area of the walkway is 516 square meters, how wide, in meters, is the walkway
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Let x be the width of walkway. Then,
(60 + 2x)(20 + 2x) - 60 × 20 = 516
(60 + 2x)(20 + 2x) = 1716
(30 + x)(10 + x) = 858
x^2 + 40x - 558 = 0
Applying standard formula and neglecting negative number,
x =~ (-40 + 62)/2 = 11.
Width of walkway is 11 m
(60 + 2x)(20 + 2x) - 60 × 20 = 516
(60 + 2x)(20 + 2x) = 1716
(30 + x)(10 + x) = 858
x^2 + 40x - 558 = 0
Applying standard formula and neglecting negative number,
x =~ (-40 + 62)/2 = 11.
Width of walkway is 11 m
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