A rectangular schoolyard is to be fenced in using the wall of the school for one side and 150 meters of fencing for the other three sides. The area in square meters of the schoolyard is a function of the length in meters of each of the sides perpendicular to the school wall.
Answers
Answer:
0,75
Step-by-step explanation:
The area of a shape is the amount of space on it.
The expression for A(x) is
The area when x = 40, is: 2800
The reasonable domain is:
The perimeter of the schoolyard is given as: 150
So, we have:
Where x and y represents the dimension of the schoolyard
The equation represents the sum of the three sides (because the 4th side is the wall of the school)
Substitute 150 for P
Make y the subject
The area (A) of a schoolyard is:
Substitute
Express as a function
The area when x = 40, is:
x cannot be less than 0.
Also, we have:
Set to 0
Rewrite as:
Divide both sides by -2
So, the reasonable domain is: The area of a shape is the amount of space on it.
The expression for A(x) is
The area when x = 40, is: 2800
The reasonable domain is:
The perimeter of the schoolyard is given as: 150
So, we have:
Where x and y represents the dimension of the schoolyard
The equation represents the sum of the three sides (because the 4th side is the wall of the school)
Substitute 150 for P
Make y the subject
The area (A) of a schoolyard is:
Substitute
Express as a function
The area when x = 40, is:
x cannot be less than 0.
Also, we have:
Set to 0
Rewrite as:
Divide both sides by -2
So, the reasonable domain is: The area of a shape is the amount of space on it.
The expression for A(x) is
The area when x = 40, is: 2800
The reasonable domain is:
The perimeter of the schoolyard is given as: 150
So, we have:
Where x and y represents the dimension of the schoolyard
The equation represents the sum of the three sides (because the 4th side is the wall of the school)
Substitute 150 for P
Make y the subject
The area (A) of a schoolyard is:
Substitute
Express as a function
The area when x = 40, is:
x cannot be less than 0.
Also, we have:
Set to 0
Rewrite as:
Divide both sides by -2
So, the reasonable domain is (0,75)