a rectangular sheet of aluminium foil is 44 cm long and 20 cm wide.a cylinder is made our of it by rolling the foil along wide. find the volume of the cylinder.
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Length of rectangular sheet = Height of cylindrical sheet h
So, Height of cylindrical sheet =44cm
According to question=>
Area of rectangular sheet = Lateral surface area of cylindrical sheet
So, l*b = 2*pi*r*h
44 *22 = 2 * 3.14 * r* 44
968 = 276.32* r
r = 968/276.32
r = 3.50
So, T. S. A. of cylindrical sheet = 2*pi*r(r+h)
=2*3.14*3.50(3.50+44)
= 21.98*47.5
= 1044.05 cm^2
3.0
So, Height of cylindrical sheet =44cm
According to question=>
Area of rectangular sheet = Lateral surface area of cylindrical sheet
So, l*b = 2*pi*r*h
44 *22 = 2 * 3.14 * r* 44
968 = 276.32* r
r = 968/276.32
r = 3.50
So, T. S. A. of cylindrical sheet = 2*pi*r(r+h)
=2*3.14*3.50(3.50+44)
= 21.98*47.5
= 1044.05 cm^2
3.0
JJUHI:
sorry but wrong answer
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0
Answer
3080cm^3
Refer to photo attached
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