Question

A rectangular sheet of aluminum foil is 44cm long and 20 cm wide. A cylinder is made out of it , by rolling it along the length. Find the volume of the cylinder

Answer 1

Note: If the rectangular sheet of 44cm length is rolled to a cylinder, then the height of the cylinder will be 44cm

Similarly, the width will be equal to the circumference of the cylinder

Circumference of the cylinder = 20 cm

=> 2πR = 20

=> 2 × $\frac{22}{7} × R = 20$

=> $\frac{44}{7} × R = 20$

=> R = $\frac{20 × 7}{44}$

=> R = $\frac{35}{11}$

So,

volume of the cylinder = πR²H

=> $\frac{22}{7} × (\frac{35}{11})^2 × 44$

=> 2 × 5 × 35 × 4

=> 1400 cm²

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Answer 2

Answer:

1400 cm^3

Step-by-step explanation:

Total surface area of aluminum foil => 44*20 = 880 cm^2

If we roll the foil along the length

Cicumference = 20 cm

Height = 44 cm

To find the volume we need the height and the radius

Now find the radius

$2\pi r = 20$

$2*22/7*r = 20$

$(44/7) * r = 20$

$r = 140/44 = 35/11$

Area of cyclinder = $\pi r^{2} h$

=> $22/7 * (35/11)^{2} * 44$

=> 1400 cm^3