Math, asked by luckswg1undunainath, 1 year ago

A rectangular sheet of dimensions 25 cm × 7 cm is rotated about its longer side. Find the volume and the whole surface area of the solid thus generated.

Answers

Answered by Ben111
75
THE SOLID WILL BE CYLINDER

Radius will be 7cm
Height will be 25cm

VOLUME = πr^2h

= 22/7×7×7×25

= 22×7×25

= 3850cm^3

TSA = 2πr(h+r)

= 2×22/7×7(25+7)

= 44(32)

= 1408cm^2

CSA = 2πrh

= 2×22/7×7×25

= 44×25

= 1100cm^2

Answered by junaida8080
2

Answer:

Hence, the volume is 3850cm^{3} and the whole surface area of the solid is 1408cm^{2}.

Step-by-step explanation:

As per the data in the given question.

The given data is as follows.

A rectangular sheet of dimension 25cm×7cm.

We have to find the volume and the whole surface area of the solid.

According to the question, the solid will be cylinder.

Radius will be (r)7cm and

Height will be (h)25cm.

As we know that,

Volume of Cylinder=πr^{2}h

Substituting the value of r and h and we will take π value as 22\7

V=\frac{22}{7}\times7\times7\times25

Numerator and Denominator 7 will get cancel.

=22\times7\times25

=3850cm^{3}

The volume is 3850cm^{3}.

Now, we have to find total surface area.

Total surface area=2πr(h+r)

=2\times\frac{22}{7} \times7\times(25+7)

Numerator and Denominator 7 will get cancel.

=2\times22(32)

=44(32)

=1408cm^{2}

Hence, the volume is 3850cm^{3} and the whole surface area of the solid is 1408cm^{2}.

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