a rectangular sheet of metal measuring 50cm by 30 cm has a semicircle of a radius 15 cmcut from each short side. find the perimeter of left
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circumference of the semicircle=pie*r
circumference = 22/7*15
circumference = 47.14
therefore perimeter = 50+50+47.14+47.14
perimeter = 194.28
circumference = 22/7*15
circumference = 47.14
therefore perimeter = 50+50+47.14+47.14
perimeter = 194.28
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