a rectangular sheet of paper 35cm×21cm can be transformed into the curved surface of a right cicular cylinder in two ways i.e, either by rolling the paper along its length or along its breadth find the ratio of the volume of the two cylinder thus formed
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Answer:
682.38 cm³ (approx) when rolled along its length
409.43 cm³ (approx) when rolled along its width
Step-by-step explanation:
Rolling along its length, the cylinder has height 21 cm and circumference (of its base) equal to 35 cm.
Let r be the radius.
Circumference = 2 π r = 35 => r = 35 / 2π
Area of base = π r² = π × 35² / 4π² = 1225 / 4π
Volume of cylinder = (1/3) × (area of base) × (height)
= (1/3) × (1225/4π) × 21
≈ 682.38 cm³ (approx)
Rolling the other way, height = 35cm and circumference = 21cm.
Let r be the radius.
Circumference = 2 π r = 21 => r = 21 / 2π
Area of base = π r² = π × 21² / 4π² = 441 / 4π
Volume of cylinder = (1/3) × (area of base) × (height)
= (1/3) × (441/4π) × 35
≈ 409.43 cm³ (approx)
Aaffuu:
iska answer ratio me ayega
The ratio is (volume of rolled along length cylinder) / (volume of along width cylinder)
= ( 35^2 x 21 ) / ( 21^2 x 35 ) [ the (1/3) and the 4pi cancel ]
= 35 / 21
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