Question

Forces of 4N and 5N are applied at origin along X-axis and Y-axis respectively. The resultant force will be(a) $\sqrt{41}N,\ \tan^{-1}(\frac{5}{4})$(b) $\sqrt{41}N,\ \tan^{-1}(\frac{4}{5})$(c) $-\sqrt{41}N,\ \tan^{-1}(\frac{5}{4})$(d) $-\sqrt{41}N,\ \tan^{-1}(\frac{4}{5})$

Answer 1

I think ur answer is c part hope it helps u dear friend