A rectangular sheet of paper 44 cm x 22 cm is rolled along its length to form a cylinder. Find the volume of the cylinder so formed.
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Answered by
24
Hey there!!
Let the length of the rectangle be the circumference of the cylindrical base of the cylinder
( 2 ) ( π ) ( r ) = 44 cm²
π ( r ) = 22
( 22 ÷ 7 ) ( r ) = 22
r = ( 22 ) × ( 7 ÷ 22 )
r = ( 1 ) × ( 7 )
r = 7 cm
Radius = 7 cm
The breadth be it's height
The formula for the cylinder = ( π ) ( r² ) ( h )
( 22 ÷ 7 ) ( 49 ) ( 22 )
( 22 ) ( 7 ) ( 22 )
3388 cm³ is the answer
______________
Let the length of the rectangle be the circumference of the cylindrical base of the cylinder
( 2 ) ( π ) ( r ) = 44 cm²
π ( r ) = 22
( 22 ÷ 7 ) ( r ) = 22
r = ( 22 ) × ( 7 ÷ 22 )
r = ( 1 ) × ( 7 )
r = 7 cm
Radius = 7 cm
The breadth be it's height
The formula for the cylinder = ( π ) ( r² ) ( h )
( 22 ÷ 7 ) ( 49 ) ( 22 )
( 22 ) ( 7 ) ( 22 )
3388 cm³ is the answer
______________
Answered by
16
Step-by-step explanation:
Dimensions of the rectangular sheet
Length = 44 cm
breadth = 22 cm
Given : Its length rolled to form a cylinder
So, height = 22 cm
length of the sheet = circumference of the base of the cylinder
Circumference = 2πr
44 = 2× 22/7 × r
r = 44×7 /44
r = 7 cm
Volume of cylinder = πr^2h
= 22/7×7×7×22
= 3388 cm^3
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