A rectangular sheet of paper of area 1320sq cm is rolled into a cylinder. If it’s volume is6930cube centimetres find dimension of the sheet
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ab=1320
v=πr*r*h=a*r/2*b=6930
r=2*6930/1320=10.5
a=2π10.5=66
b=20
v=πr*r*h=a*r/2*b=6930
r=2*6930/1320=10.5
a=2π10.5=66
b=20
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here volume is πr^2h = 6930
thus r^2h =6930×7/22 =2205
now lateral surface area is 2πrh=1320
rh =1320×7/44= 210
thus r is r^2h/rh
=2205/210= 10.5cm =r
so. h in 2πrh is
1320/2×22/7×10.5
=1320/66= 20cm
now area l×b =1320
l =1320/20 =66cm
b=20cm
thus r^2h =6930×7/22 =2205
now lateral surface area is 2πrh=1320
rh =1320×7/44= 210
thus r is r^2h/rh
=2205/210= 10.5cm =r
so. h in 2πrh is
1320/2×22/7×10.5
=1320/66= 20cm
now area l×b =1320
l =1320/20 =66cm
b=20cm
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