a rectangular sheet of paper of dimensions 44 cm * 14 cm is rolled along its length and a cylinder is formed . find the surface area of the cylinder
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38
Length of rectangular sheet = 44 cm
breadth of rectangular sheet = 14 cm
Now, it is rolled so length becomes circumference and breadth becomes height
Circumference of cylinder = 2πr
44 = 2×22÷7×r
44×7÷44 = r
7 = r
Radius of cylinder = 7 cm
height of cylinder = 14 cm
T.S.A of cylinder = 2πr(h+r)
= 2×22÷7(14+7)
= 44(21)
= 924cm square
breadth of rectangular sheet = 14 cm
Now, it is rolled so length becomes circumference and breadth becomes height
Circumference of cylinder = 2πr
44 = 2×22÷7×r
44×7÷44 = r
7 = r
Radius of cylinder = 7 cm
height of cylinder = 14 cm
T.S.A of cylinder = 2πr(h+r)
= 2×22÷7(14+7)
= 44(21)
= 924cm square
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12
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