Math, asked by mihir341, 1 year ago

A rectangular sheet of paper of dimensions 44cm×18cm is rolled along its length to form a cylinder. Find the total surface area of the cylinder so formed.

Answers

Answered by VaibhavDangaich1
61

dimensions \: of \: sheet \\ l = 44cm \\ b = 18cm \\ this \: sheet \: is \: rolled \: along \: its \: length \: so \\ length \: becomes \: the \: circumference \\ 2\pi r = 44 \\ 2 \times  \frac{22}{7}  \times r = 44 \\  \frac{44}{7}  \times r = 44 \\ r = 44 \times  \frac{7}{44}  \\ r = 7 \: cm \\ now \\ tsa = 2\pi \: r(r + h) \\ 2 \times  \frac{22}{7}  \times 7(7 + 18) \\ \frac{44}{7}  \times 7 \times 25 \\ 44 \times 25 \\ 1100cm {}^{2}
Answered by Vatsalya27603
10
Height=44
Breadth becomes circumference hence 2 pie r
R=63/22
T.s.a=2 pie r (r+h)
Solve it answer you will get will be 9/11×1031
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