a rectangular swimming pool 30 M long 20 m wide and 1.5 m deep is to be tiled if each tile is 50 cm and 50 cm, how many tiles will be required?(remember there is no roof for the pool)
Arya79:
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Answered by
16
Tsa =lb+2(bh+lh)=600+ 2*(45+30)=600 + 150=750 m²
area of each tile = 0.25m²
number of tiles=75000/25=3000
area of each tile = 0.25m²
number of tiles=75000/25=3000
Answered by
63
area of swimming pool =lateral surface area + area of Base
=2 h (l+b)+l×b
=2×1.5 (30+20)+30×20
=3 (50)+600
=150 +600
=750m^2
now area of tiles
=side ×side
=0.5×0.5
=.25m^2
so the tiles require in pool
750 /0.25
=3000
=2 h (l+b)+l×b
=2×1.5 (30+20)+30×20
=3 (50)+600
=150 +600
=750m^2
now area of tiles
=side ×side
=0.5×0.5
=.25m^2
so the tiles require in pool
750 /0.25
=3000
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