Math, asked by jesonzacarias84, 5 months ago

A rectangular table has an area of 27 ft² and a perimeter of 24 ft.what are the dimensions of the table​

Answers

Answered by Cottonnn
52

Answer: 9ft and 3ft.

Explanation:

Area: 9 x 3 = 27.

Preimeter: 9 + 9+ 3 + 3 = 27

Hope this helped.

Answered by amourya13
40

Answer:

27

Step-by-step explanation:

So we know the formula for area is:

A=LW

And perimeter is:

P=2L+2W

We know area is 27 and perimeter is 24, so our equations are:27=LW

24=2L+2W

To solve as a system of equations, lets isolate L on the second equation.

24 = 2L + 2W

24 -2W = 2L

12 - W = L

And Plug this into the first equation

27 = (12-W)W

27 = 12W - W2

This looks like a quadratic, so let's bring everything to the left side and factor.

W2 - 12W + 27 = 0

(W-9)(W-3)=0

W=9 or W=3

Plug both of these into 27=LW to find L

27=9L

L=3 when W=9

or 27=3L

L=9 when W=3

These both say pretty much the same thing, so this table is 9 feet long and 3 feet wide.

or

area of a rectangular = l x b

27 = 9 x 3

Perimeter of a rectangular = l + l + b + b

24 = 9 + 9 + 3 + 3

dimension of the table = 9 * 3 = 27

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