Question

A rectangular tank 10" by 8" by 4" is filled with water. if all of the water is to be transferred to cube-shaped tanks, each one 3 inches on a side, how many of these smaller tanks are needed?

Answer 1

The volume of the rectangular tank is:

10 inches by 8 inches  by 4 inches

10 × 8 × 4 = 320 inches³

The volume of the smaller cubical tanks of side 3 inches:

3 inches by 3 inches by 3 inches

3 × 3 × 3 = 27 inches ³

Divide the volume of the bigger tank by the smaller tank to find the number of smaller tanks that will be needed:

320 inches ³ / 27 inches ³   = 11. 851851 tanks

Since you do not have a fraction of the small tank, you will need 12 tanks. However the 12th tank will not be filled.

The number of tanks required are 12

Answer 2

Given:

L= 10 inches ,B= 8 inches , H=4 inches

Volume of the rectangular tank = L× B×H

= 10 × 8 × 4 = 320 inches³

Given:
Side of smaller cube= 3 inches

Volume of the cube = side ³

Vol. Of cube tank = 3×3×3= 27 inches³

Number of smaller tanks = vol. Of rectangular tank / vol. Of cube tank

= 320 inches ³ / 27 inches ³ = 11. 85 tanks

Number of smaller tanks = 11.85 inches³ ≈ 12 (approx)

Hence, the Number of tanks required = 12


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